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When you bet outside you can give the dealer $40 and he places $10 bets on the four, five, nine and ten. The five/nine pay $14 (At 7:5) And the four/ten pay $18 (At 9:5). The combination of the four numbers will roll 14 times (In 36) compared to six times for the seven, giving you more than a 2:1 Advantage. If you continue to place the outside numbers for 36 sample rolls, you’ll win $220 (6 X $18 + 8 x $14). In worst case you’ll lose all $40 six times (From the seven) or $240 - resulting in a net loss of $20. It’s unlikely to happen but still, you won’t lose too much money betting in this manner. Wanna know the secrets that the craps pros use to turn the outside numbers into real profit makers? Let'S find out! To turn these outside numbers into profit makers you need to buy all of them instead of placing them. You can buy the four and ten in many casinos for $39 and only pay $1 vig each. You should also be able to buy the five and nine also for $38 with the same $1 vig for each number. So, now you have $38 on the five/nine, and $39 on the four/ten. In 36 theoretical rolls, you should win on these numbers 14 times - three times each on the four and ten, and, four times each on the five and nine. On the four and ten you’ll win $78 (At 2:1). Since the four and ten roll three times each (Total six times) you win a total of $468 (6 X $78). On the five and nine, you’ll win $57 (At 3:2). Since the five and nine roll four times each (Total eight times) you win a total of $456 (8 X $57). So the total possible win (If you win all 14 of your bets) is $468 plus $456 or $924. Read more